Warriors guard Stephen Curry will be named the NBA’s Most Valuable Player, according to multiple league sources.
Official announcement will come this week, CSN Bay Area reported, likely on Monday between Games 1 and 2 of the Western Conference semifinals series between the Warriors and the Memphis Grizzlies.
The timing of the announcement, one source said Sunday morning, remains flexible and could become between Games 2 and 3 of the Warriors-Grizzlies series.
Curry, who on Sunday scored a game-high 22 points in a 101-86 Warriors victory over Memphis, will become the first Warrior in the franchise’s 53-year California history to win the league’s highest individual honor.
The sixth-year point guard averaged 23.8 points per game (sixth in the league), 7.7 assists (sixth) and 2.04 steals (fourth). He shot 44.3 percent from 3-point distance (fourth), 91.4 percent on free throws (first) and his 48.7 percent overall shooting percentage led all point guards.